Question

63gifts cost is 3000.in this there are 100rs And 25rs cost. Then how many gifts

Answer 1

Let the number of prizes of money 100 be x, and the number of prizes of cost 25 be y ;
x+y = 63
y = 63-x -------(1)

100x+25y = 3000
4x+y = 120
y = 120-4x ------(2)

63-x = 120-4x
4x-x = 120-63
3x = 57
x = 19

y = 63-x = 63-19
y = 44

Hence the number of prizes of cost 100 each are 19 while other type of prizes are 44
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Answer 2

Explanation:

https://brainly.in/question/5053028

63gifts cost is 3000.in this there are 100rs And 25rs cost. Then how ...

lets assume that x number of gifts contain Rs 100 and y number of gifts contain Rs25

Now, according to the question

100x+25y=3000--------(i)

and 

x+y=63.............(i)

performing (i)-25(ii) we get

75x=1425

x=19

substituting in (ii) we get

y=63-19 = 44

So number of prizes of 100 type = 19 and number of prizes of type 25 is 44

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