Question

63p^2×q^2 - 7 (minus 7 is not on the power it's the base)

Answer 1

Answer:

(3pq)(3pq)

Step-by-step explanation:

63p^2 × q^2 -7

7(9p^2 ×q^2) =0

9p ^2 × q^2

(3pq)^2

(3pq) (3pq).

hope this helps you....❣️❣️