Question

(63x^2-19x-20)÷(9x^2+5)
$63x { } {}^{2} - 19x - 20 \div 9x {}^{2} + 5$
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Answer 1

Step-by-step explanation:

Good Morning ☆☆☆

$63x ^{2} - 19x - 20 \div 9x ^{2} + 5$

$7x {}^{2} - 19x - 20 + 5$

$7x {}^{2} - 19x - 15$

$it \: is \: your \: answer \: because \: of \: x {}^{2} x \: they \: couldnot \: be \: divide$

$so \: thanks$

Answer 2

Step-by-step explanation:

63

${63x }^{2} \div {9x }^{2} - 19x - 20 + 5 \\ {7x}^{2} - 19x - 15$

This is your answer.

Good morning

please Mark as brainlist.