Question

64^-1/2

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Answer 1

Answer:

$given \: that \\ \: {(64)}^{ \frac{ - 1}{2}} \\ \: = > ( {2}^{6) \frac{ - 1}{2} } \\ \: ( {a}^{m})^{n} = {a}^{mn} \: \\ = > {2}^{6 \times \frac{ - 1}{2} } \\ \: = > {2}^{ - 3} \\ \: we \: know \: that \: {a}^{ - n} = \frac{1}{ {a}^{n} } \\ \: {2}^{ - 3 = \frac{1}{ {2}^{3} } } = > \frac{1}{8}$

Answer 2

Answer:

\begin{gathered}given \: that \\ \: {(64)}^{ \frac{ - 1}{2}} \\ \: = > ( {2}^{6) \frac{ - 1}{2} } \\ \: ( {a}^{m})^{n} = {a}^{mn} \: \\ = > {2}^{6 \times \frac{ - 1}{2} } \\ \: = > {2}^{ - 3} \\ \: we \: know \: that \: {a}^{ - n} = \frac{1}{ {a}^{n} } \\ \: {2}^{ - 3 = \frac{1}{ {2}^{3} } } = > \frac{1}{8} \end{gathered}

giventhat

(64)

2

−1

=>(2

6)

2

−1

(a

m

)

n

=a

mn

=>2

6×

2

−1

=>2

−3

weknowthata

−n

=

a

n

1

2

−3=

2

3

1

=>

8

1