Math, asked by jitugajjar097, 10 months ago

64^-1/3( 64^1/3-64^2/3)

Answers

Answered by PsychoUnicorn
9

\huge{\underline{\tt{\blue{Answer-}}}}

\longrightarrow \tt \: ( {4}^{3}) {  {}^{ \frac{ - 1}{3} } }   \:  \bigg \{( {4}^{3} ) {}^{ \frac{1}{3} }  - ( {4}^{3} ) {}^{ \frac{2}{3} }  \bigg \} \\  \\  \\  \longrightarrow \tt \:  {4}^{ - 1}  \:  \{4 -  {4}^{2} \} \\  \\  \\  \longrightarrow \tt \:  \frac{1}{4}   \:  \:  \:  \{4 - 16 \} \\  \\  \\  \longrightarrow \tt \:  \frac{1}{4}  \times ( - 12) \\  \\  \\  \longrightarrow \tt \frac{ - 12}{4}  \\  \\  \\  \longrightarrow \tt \green{ - 3}

Answered by MrChauhan96
13

\bf\orange{\underline{\underline{Question}}}

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64^-1/3( 64^1/3-64^2/3)

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\bf\orange{\underline{\underline{Solution}}}

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\rightarrow \tt \: ( {4}^{3}) { {}^{ \frac{ - 1}{3} } } \: \bigg \{( {4}^{3} ) {}^{ \frac{1}{3} } - ( {4}^{3} ) {}^{ \frac{2}{3} } \bigg \} \\ \\ \\ \rightarrow \tt \: {4}^{ - 1} \: \{4 - {4}^{2} \} \\ \\ \\ \rightarrow \tt \: \frac{1}{4} \: \: \: \{4 - 16 \} \\ \\ \\ \rightarrow \tt \: \frac{1}{4} \times ( - 12) \\ \\ \\ \rightarrow \tt \frac{ - 12}{4}

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\large{\underline{\tt{\red{ Final\: answer -\:\:\:3}}}}

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