Question

64×(1/8^2)^3=8n
Find the answer with process
$64 \times ( \frac{1}{8^{2} } )^{3} = 8n$
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Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$we \: know \: that \\ 64 = 8 \times 8 = {(8)}^{2} \\ \\ now \\ \\ 64 \: \: {( \dfrac{1}{ {8}^{2} })}^{3} = {8}^{n} \\ \\ {(8)}^{2} \dfrac{ {1} ^{3} }{ {( {8}^{2} )}^{3} } = {8}^{n} \\ \\ \dfrac{ {8}^{2} \times 1}{ {8}^{6} } = {8}^{n} \\ \\ {8}^{2 - 6} = {8}^{n} \\ {8}^{ - 4} = {8}^{n} \\ n = - 4$