Question

64^12÷(16^4)^3×1/4^10




please let me know the answer with steps​

Answer 1

Answer:

answer is 16

hope it helps

Answer 2

$\huge\mathfrak{\red{Answer}}$

${4}^{ - 10}$

Step-by-step explanation:

$\frac{ {64}^{12} }{ {(64}^{4}) {}^{3} } \times \frac{1}{ {4}^{10} }$

As we know,

$({a}^{n} ) {}^{m} = {a}^{n \times m}$

Therefore

$\frac{ {64}^{12} }{ {64}^{4 \times 3} } \times \frac{1}{ {4}^{10} }$

$= > \frac{ {64}^{12} }{ {64}^{12} } \times \frac{1}{ {4}^{10} }$

Also,

${a}^{ - n} = \frac{1}{ {a}^{n} }$

Therefore,

$= > \: \frac{ {64}^{12} }{64 {}^{12} } \times {4}^{ - 10}$

We know that

$\frac{ {a}^{n} }{ {a}^{m} } = {a}^{n - m}$

Hence, it becomes

${64}^{12 - 12} \times {4}^{ - 10}$

${64}^{0} \times {4}^{ - 10}$

Now,

${a}^{0} = 1$

therefore,

$= > 1 \times {4}^{ - 10}$

${4}^{ - 10} or \frac{1}{ {4}^{10} }$