(64/125)^-2/3 ÷ 1/ (264/625)^1/4 + (√25/^3√64 )^0 solve it by applying indices rule
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Answered by
4
Answer:
(
125
64
)
−2/3
÷
(256/625)
1/4
1
+(
3
64
(
25
)
)
0
⇒ (
5
4
)
−2
÷
5
4
1
+1
⇒ (
5
4
)
−2
×(
5
4
)
1
+1
⇒ (
5
4
)
−2+1
+1
⇒ (
5
4
)
−1
+1
⇒
4
5
+1
⇒
4
9
∴ (
125
64
)
−2/3
÷
(256/625)
1/4
1
+(
3
64
(
25
)
)
0
=
4
9
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