Math, asked by rameshtiwari, 1 year ago

(64/125)^-2/3+(256/625)^-1/4+(3/7)^0 evaluate

Answers

Answered by sris99
16
=(125/64)^2/3 + (625/256)^1/4 +1

=(5/4)^2 + (5/4) + 1

=25/16 + 5/4 + 1

= 61/16

= 3.81
Answered by BloomingBud
16

 ({ \frac{64}{125} )}^{ \frac{ - 2}{3} }  +  {( \frac{256}{625} )}^{ \frac{ - 1}{4} }  +  {( \frac{3}{7} )}^{0}  \\  \\  \\  (\frac{ \sqrt[3]{64} }{ \sqrt[3]{125} } ) +  (\frac{ \sqrt[4]{256} }{ \sqrt[4]{625} } ) + 1 \\  \\  \\(  { \frac{4}{5}) }^{ - 2}  +  { (\frac{4}{5}) }^{ - 1}  + 1 \\  \\  \\  ( { \frac{5}{4} )}^{ - 2}  +  \frac{5}{4}  + 1 \\  \\ \\  \frac{25}{16}  +  \frac{5}{4}  + 1 \\  \\  \\  taking \:  \: lcm \:  \: 16 \\  \\  \\  \frac{25 + 20 + 16}{16}  \\  \\  \\  \frac{61}{16}
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