64-176x+121x^2 find the square root
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Answered by
12
121x²-176x+64
=(11x)²-2.(11x)8 +8²
= (11x-8)²
squre root of (11x-8)² is = 11x-8
Answered by
7
Answer:
firstly rearrange it in x form 1st x^2 then x then constant
therefore
121 x^2 - 176 x + 64
= (11x)^2 - 2 *(11x)*8 + 8^2
=so, (11x - 8)^2
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