Question

(64)^2/3-(1/81)^-1/4+8^2/3•(1/2)^-1•3^0​

Answer 1

Answer:

I will not understand clarfully

Answer 2

$({64})^{ \frac{2}{3} } - ( { \frac{1}{81} })^{ \frac{ - 1}{4} } + ( {8)}^{ \frac{2}{3} } \times ( { \frac{1}{2} })^{ - 1} \times {3}^{0} \\ {x}^{0} = 1 \\ ( {4}^{ {3})^{ \frac{2}{3} } } - ( \frac{1}{ {3}^{4} } ) {}^{ \frac{ - 1}{4} } + ( {2}^{ {3})^{ \frac{2}{3} } } \times \frac{ {1}^{ - 1} }{ {2}^{ - 1} } \times 1 \\ {4}^{2} - \frac{ {1}^{ \frac{ - 1}{4} } }{ ({3}^{4} ){}^{ \frac{ - 1}{4} } } \times {2}^{2} \times \frac{2 {}^{1} }{ {1}^{1} } \times 1 \\ {4}^{2} - \frac{ {1}^{ \frac{ - 1}{4} } }{ {3}^{ - 1} } \times {2}^{2} \times \frac{2}{1} \times 1 \\ \\ 16 - \frac{ {3}^{1} }{ {1}^{ \frac{1}{4} } } \times 4 \times 2 \\ 16 - \frac{3}{1} \times 8 \\ 16 - 24 = - 8$

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