Question

[6⁴×(½)²] ÷(⅓)¯³
Pls give fast answer ​

Answer 1

Question:

To Find the value of $[6^4\times\frac{1}{2}^2]\div\frac{1}{3}^-^3$

Given:

$[6^4\times\frac{1}{2}^2]\div\frac{1}{3}^-^3$

To Find:

$[6^4\times\frac{1}{2}^2]\div\frac{1}{3}^-^3$

Formula Used:

$(\frac{a}{b})^-^n=(\frac{b}{a})^n$

Solution:

$[6^4\times\frac{1}{2}^2]\div\frac{1}{3}^-^3\\\\\\(\frac{a}{b})^-^n=(\frac{b}{a})^n$

$[6^4\times\frac{1}{2}^2]\div(\frac{3}{1})^3\\\\\\=6\times6\times6\times6\times\frac{1}{2}\times\frac{1}{2}\div3\times3\times3\\\\\\=3\times3\times6\times6\times\frac{1}{3}\times\frac{1}{3}\times\frac{1}{3}\\\\\\=2\times6\\\\\\=12$

Answer:

12