Question

64/27x³+27/64y³+4x²y+9/4xy²

Answer 1

Answer:

$({ { \frac{4}{3}x } + \frac{3}{4}y })^{3}$

Step-by-step explanation:

there is your answer mate solve it by using (a + b)³ = à³+b³ + 3ab (a+b)

and 64 is cube of 4 and 27 is cube of 3