Question

64.50
Solve the word problem.
I am a number between 200 and 300. I am divisible by 3. If you subtract 7 from me, you can
divide me by 10 and 20. If you add 3 to me. I am divisible by 9. What number am 19
TESTS OF DIVISIBIUTY
Name
Teacher's signature​

Answer 1

Answer:

The answer is 267...

Step-by-step explanation:

Note that 267 is divisible by 3

267-7=260 which is divisible by 10 and 20

267+3=270 which is 9(30)