Question

64½(64½+1) find the value​

Answer 1

Answer:

$\sqrt{64}(\sqrt{64}+1)=72$

Step-by-step explanation:

$\sqrt{64}(\sqrt{64}+1)\\=\sqrt{8^{2}}(\sqrt{8^{2}}+1)\\=8(8+1)\\=8\times 9 \\=72$

Therefore,

$\sqrt{64}(\sqrt{64}+1)=72$

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Answer 2

${\red{\mathbb{\boxed{ANSWER}}}}$

${64}^{1 \div 2} ( {64}^{1 \div 2} + 1 ) \\ 8(8 + 1) \\ 8 \times 9 \\ 72$

Hope It Helps