Question

64÷8-2[3+{7-3(3+ 4-2)}]​

Answer 1

☞ 64 ÷ 8 - 2 [ 3+ { 7-3 ( 3+4-2 )}]

= 64 ÷ 8 - 2 [ 3+ { 7 - 3 (5)}]

= 64 ÷ 8 - 2 { 3+ (-8)}

= 64 ÷ 8 - 2 ( 3 - 8)

= 64 ÷ 8 - 2 (-5)

= 8 - 2 (-5)

= 8 + 10

= 18

So, the answer is 18.

HOPE IT WILL HELP YOU☜

Answer 2

Hey Mate !!

Given :

• 64÷8-2[3+{7-3(3+ 4-2)}]

To Find :

• The Answer by evaluating it.

Required Solution :

$✰\:\:\tt \:64 \div 8-2(3+(7-3(3+4-2))) \\\\\ : \implies \tt \: 8-2\left(3+7-3\left(3+4-2\right)\right) \\\\\ : \implies \tt \:8-2\left(3+7-3\left(7-2\right)\right) \\\\\ : \implies \tt \:8-2\left(3+7-3\times 5\right) \\\\\ : \implies \tt \:8-2\left(3+7-15\right) \\\\\ : \implies \tt \:8-2\left(3-8\right) \\\\\ : \implies \tt \:8-2\left(-5\right) \\\\\ : \implies \tt \:8-\left(-10\right) \\\\\ : \implies \tt \:8+10 \\\\\ \underline{ \boxed{ \frak{➠ \: 18}}} \: \: ✰$

.°. The Answer is 18.

✰ Hope it helps u ✰