Question

64-(a +1)²please help me buddy ​

Answer 1

Answer:

$64 - {(a + 1)}^{2} \\ = 64 - ( {a}^{2} + {1}^{2} + 2a) \\ = 64 - {a}^{2} - 1 - 2a \\ = 63 - {a}^{2} - 2a \\ = - {a}^{2} - 2a - 63$

Answer 2

Answer:

8^2-(a+1) ^2

is of form a^2-b^2=(a+b) (a-b)

(8+a+1) (8-a-1)

(9+a) (7-a)