64. A block of mass 20kg is placed on a rough horizontal plane and a horizontal force of 12N is applied. If coefficient of friction is 0.1 the frictional force acting on it is, 1) 20 N 2) 12 N 3) 8 N 4) 28 N
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Answer:
3. 8 N
Explanation:
normal reaction= 20g = 200 N
friction = - (0.1× 200 )= -20 N
therfore net force= 20-12 = 8 N
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