Question

64. A particle of mass 'm' moves in a circular path of
radius 2m with a speed of 10m/s. Calculate the
time after which the magnitude of change in its
momentum becomes equal to its initial momentum
wila
sec
u N
oila
(4) Not possible​

Answer 1

0.2 sec

Explanation:

Mass of particle=m

Radius of circular path,r= m

Initial speed,v=10m/s

We know that by Newton's second law

Change in momentum=Ft

Where F=$\frac{mv^2}{r}$

v=Speed of object

r=Radius of circular path

According to question

Change in momentum=Initial momentum=mv

$mv=\frac{mv^2}{r}t$

$t=\frac{r}{v}=\frac{2}{10}=0.2 s$

Hence, after 0.2 s the magnitude of change in its momentum becomes equal to its initial momentum.

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