Question

64 and equal drops each of capacity 5 uf combine to form a big drop what is the capacity of big drop

Answer 1

Radius of big drop=R

Radius of small drop=r

 

volume of big drop=64×volume of small drop

we conclude 

R=4r

Capacitance of a small drop= 4πr=5uf----------(1)

Capacitance of large drop= 4πR=Cuf...............(2)

Taking ratio we get C=20uf 

Answer 2

We first find volume of big drop
volume of big drop=64 x volume of small drop
4/3pi.R^3=64 x 4/3pi.r^3
R=4r
because capacitance of solid spherical body directly proportion to radius
hence big drop capacitance =4 x capacitance of small

capacitance of big drop=20F


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