64 g of an organic compound has 24g of carbon and 8 g hydrogen and the rest is oxygen. What is the empirical formula of the compound ?
Answers
Answered by
54
oxygen present in compound =64-24-8
=32g
for carbon moles=24/12=2
for hydrogen moles =8/1=8
for oxygen =32/16=2
molar ratio =1:4:1
empirical formula=CH4O
=32g
for carbon moles=24/12=2
for hydrogen moles =8/1=8
for oxygen =32/16=2
molar ratio =1:4:1
empirical formula=CH4O
Answered by
0
Answer:
64gm of an organic compound has 24g carbon and rest hydrogen and oxygen. the empirical formula of tha compound is. Now if we remove this qty of carbon from the mass of the total organic compound = 64-24=40 g - we are left with this mass for both oxygen and hydrogen.
Similar questions