Question

64 g of methanol is dissolved in 126 g of water the mole fraction of methanol in the solution is?

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Answer 1

Answer:

Correct option is

B

0.22,0.78

Given conditions ⇒

Mass of the Methanol = 60 g.

Molar mass of the Methanol = 32 g/mole.

∵ No. of moles of Methanol =

Molar Mass

Mass

∴ No. of moles = 60/32

= 1.875 mole.

Mass of the Water = 120 g.

Molar mass of the water = 18 g/mole.

∴ No. of moles of Water =

Molar mass

Mass

.

= 120/18

= 6.67 mole.

Now, Total number of moles in a solution = No. of moles of Methanol + No. of moles of water.

= 1.875 + 6.67

= 8.545 moles.

Now,

Mole Fraction of Methanol in the solution =

Total number of moles in a solutions

No. of moles of Methanol

.

= 1.875/8.545

= 0.22

Mole Fraction of Water in the solution =

Total number of moles in a solution

No. of moles of water

.

= 6.67/8.545

= 0.78

Answer 2

Explanation:

Ans of this question is 4/7