Question

64 g of oxygen (assume ideal behaviour) at 27°C undergoes reversible isothermal expansion from 2.5
L to 25 L. The values of Au, w and q are (in cal)
1)0,2764, -2764
2) 0, -2764, 2764
3) 2764, -2764,0
4)-2764, 0, 2764
​

Answer 1

Answer:

1) 0,2764.-2764

Explanation:

Δu⇒0 since ΔT ⇒0 as the process is isothermal.

as the process is isothermal and reversible , W = -2.303nRTlog(V2/V1)

n = 64g/32g ⇒ 2 mol

R = 8.314

T = 3OO K

substituting W =- 2×8.314×300×log10 ⇒ 11490 J

Divide by 4.18 , value would be about -2764 calories = W

as q = -w , q = 2764

(workbook q no.6)

Answer 2

Answer:

a)

Explanation:

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