Question

64 identical drops each of capacity 5 frl combine to from a big drop. capacity of the big drop will be?​

Answer 1

Answer:

Capacitance for drop => R/kwhere R is the radii.

From Volume conservation, Vnet = 64V

R^3 = 64r^3

R = 4r

For big drop, C = R/k.......(1)

For small dop, 5 = r/k........(2)

Divdng the eqns. we get,

C = 5*(R/r) => 5*4 = 20 mF. mark my answer brainliest