Question

64. If a car at rest accelerates uniformly to a speed of
144 km/h in 40 seconds, it covers a distance of :
(1) 200 m
(2) 400 m
(3) 1440 m
(4) 2980 m​

Answer 1

Answer:

Given,

Initial speed (u) = 0 m/s

Final speed (v) = 144 km/hr

= (144*5)/18 m/s

= 40 m/s

Time (t) = 40s

Let the Distance be denoted as S.

Acceleration (a) = (v-u)/t

= 40/40 m/s²

= 1 m/s²

∴ v² = u²+2aS

= (40)² = [2*1*S]

= 1600 = 2S

= 800 m = Distance

I hope this helps.