64.If the block in the shown arrangement is acted upon by a constant force F for t> 0, its
maximum speed will be:
(A) F/ Vmk
(B) 2 F/mk
(C) F/2mk
(D) 2F /mk
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Answer:
The correct option is (A): F/√K/m
Explanation:
As we know that
F = kx
Since x = F/k
From work energy theorem
Work done = Δ K.E
Fx + (-1/2Kx^2) = 1/2 mv^2 - 0
Kx^2 -1/2Kx^2 = 1/2 mv^2
1/2Kx^2 = 1/2 mv^2
After cancellation:
Kx^2 = mv^2
V = x √K/m
Put the value of x
V = F/k x √K/m
After cancellation the equation becomes:
V = F / √K/m
Thus the maximum speed will be V = F / √K/m.
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