64 power 1 by 2
![64 power 1by2 (64 \: 1 \: by \: 2 + 1 64 power 1by2 (64 \: 1 \: by \: 2 + 1](https://tex.z-dn.net/?f=64++power+1by2+%2864+%5C%3A+1+%5C%3A+by+%5C%3A+2+%2B+1)
64 1 by 2 + 1
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64power 1by 2 +1=33. please solve my question.
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