Question

64 smaller water droplets each of radius 4mm are collapsed to formed a bigger water droplet. Calculate the ratio of their (small/big) surface charge densities?​

Answer 1

Explanation:

By Volume Conservation we can find radius of bigger sphere

$\frac{4}{3}\pi {4}^{3} \times 64 = \frac{4}{3}\pi {r}^{3}$

we get. r = 16 mm

let there will be a total charge q on all the 64 smaller water droplets. So there will be a total charge on bigger sphere will also be q by charge conservation.

$\frac{q}{4\pi {4}^{2} \times 64 } \div \frac{q}{4\pi {16}^{2} }$

From calculating it we get... 1: 4 Answer

( Sigma = Q ÷ Area )

Thank you