Question

64. The gravitational field strength at a point P on the earth's surface is numerically equal to
A. The acceleration of free fall at p
B. The change in potential energy per unit distance from
C. The force acting on anybody placed at p D. The Work done in bringing unit mass from infinity to p​

Answer 1

Gravitational potential energy    U=  

r

−GMm

​  

 

Gravitational potential     V=  

r

−GM

​  

 

So, gravitational potential energy per unit mass gives the gravitational potential at tht point.

Answer 2

Answer:

The Gravitational Field

Note that the field is numerically equal to the acceleration due to gravity at the location of the mass. On Earth's surface, the strength of the gravitational field is 9.8N/kg. It is independent of the size of the mass.