Math, asked by pj3436701, 5 hours ago

6400 were lent to Feroz and Rashmi a 15% per annum for 3 and 5 years respectively. Find the difference in the interest paid by them​

Answers

Answered by ItzYourCrushBaby
4

Answer:

Given, Feroz borrowed 6400 for 3 1/2 yr at

15%

Here,

P₁ = ₹ 6400, T₁ = 3 ½¹1 = 2 yr and I_{1} = (P_{1}*R_{1} * T_{1})/100 6400 x 15 x 7 100 x 2 = 15% =3360

Rashmi borrowed 6400 for 5 yr at 15%.

Here, P 2 =8.6400.R 2 =15\% and T_{2} = 5yr I_{2} = (P_{2}*R_{2} * T_{2})/100 6400 x 15 x 5 100

=4800

Difference between interests = 4800 - 3360 = ₹1440

Hence, the difference in interest, paid by them is 1440.

Step-by-step explanation:

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Answered by nihasrajgone2005
2

Answer:

Given, Feroz borrowed 6400 for 3 1/2 yr at

Given, Feroz borrowed 6400 for 3 1/2 yr at15%

Given, Feroz borrowed 6400 for 3 1/2 yr at15%Here,

Given, Feroz borrowed 6400 for 3 1/2 yr at15%Here,P₁ = ₹ 6400, T₁ = 3 ½¹1 = 2 yr and I_{1} = (P_{1}*R_{1} * T_{1})/100 6400 x 15 x 7 100 x 2 = 15% =3360

Given, Feroz borrowed 6400 for 3 1/2 yr at15%Here,P₁ = ₹ 6400, T₁ = 3 ½¹1 = 2 yr and I_{1} = (P_{1}*R_{1} * T_{1})/100 6400 x 15 x 7 100 x 2 = 15% =3360Rashmi borrowed 6400 for 5 yr at 15%.

Given, Feroz borrowed 6400 for 3 1/2 yr at15%Here,P₁ = ₹ 6400, T₁ = 3 ½¹1 = 2 yr and I_{1} = (P_{1}*R_{1} * T_{1})/100 6400 x 15 x 7 100 x 2 = 15% =3360Rashmi borrowed 6400 for 5 yr at 15%.Here, P 2 =8.6400.R 2 =15\% and T_{2} = 5yr I_{2} = (P_{2}*R_{2} * T_{2})/100 6400 x 15 x 5 100

Given, Feroz borrowed 6400 for 3 1/2 yr at15%Here,P₁ = ₹ 6400, T₁ = 3 ½¹1 = 2 yr and I_{1} = (P_{1}*R_{1} * T_{1})/100 6400 x 15 x 7 100 x 2 = 15% =3360Rashmi borrowed 6400 for 5 yr at 15%.Here, P 2 =8.6400.R 2 =15\% and T_{2} = 5yr I_{2} = (P_{2}*R_{2} * T_{2})/100 6400 x 15 x 5 100=4800

Given, Feroz borrowed 6400 for 3 1/2 yr at15%Here,P₁ = ₹ 6400, T₁ = 3 ½¹1 = 2 yr and I_{1} = (P_{1}*R_{1} * T_{1})/100 6400 x 15 x 7 100 x 2 = 15% =3360Rashmi borrowed 6400 for 5 yr at 15%.Here, P 2 =8.6400.R 2 =15\% and T_{2} = 5yr I_{2} = (P_{2}*R_{2} * T_{2})/100 6400 x 15 x 5 100=4800Difference between interests = 4800 - 3360 = ₹1440

Given, Feroz borrowed 6400 for 3 1/2 yr at15%Here,P₁ = ₹ 6400, T₁ = 3 ½¹1 = 2 yr and I_{1} = (P_{1}*R_{1} * T_{1})/100 6400 x 15 x 7 100 x 2 = 15% =3360Rashmi borrowed 6400 for 5 yr at 15%.Here, P 2 =8.6400.R 2 =15\% and T_{2} = 5yr I_{2} = (P_{2}*R_{2} * T_{2})/100 6400 x 15 x 5 100=4800Difference between interests = 4800 - 3360 = ₹1440Hence, the difference in interest, paid by them is 1440.

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