Question

64³+24³/64²+24²-64*24 find using identity​

Answer 1

${ x}^{3 } + {y}^{3} = (x + y)( {x }^{2} + {y}^{2} - xy)$
$so \\ \\ \\ \binom{(64 + 24)( {64}^{2} + {24}^{2} - 64 \times 24) } { {64}^{2} + {24 }^{2} - 64 \times 24 }$
$64 + 24 = 88$