Question

643. A river is flowing from west to east at a speed of 5 m/min. A man on the south bank of the river, capable
of swimming at 10 m/min in still water, swims across the shortest path distance. In what direction should
he swim?​

Answer 1

Answer:

⇒θ=30

Direction is 30∘ east of south

Explanation:

Let the swimmer swims at an angle θ with the

Vertical

From figure

sinθ = vr/vb

where vr is velocity of river, vb is velocity of man.

Given

vr=5m min−1,vb

=10m min−1

∴ sinθ=5/10=1/2

⇒θ=30

The component 10sinθ, of swimmers velocity will

cancel the velocity of river and the swimmer takes

the shortest distance to the south. Therefore,

direction is 30∘ east of south

Answer 2

Explanation:

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