Question

[64a^12]^-2/3 ÷[27b^6]^-1/3 evaluate using laws of exponents pls do it fast

Answer 1

Answer:

3b² / 16a⁸

Step-by-step explanation:

[64a¹²]⁻$\frac{2}{3}$ = [4a⁴]⁻² = 1/[4a⁴]² = 1/16a⁸..........(1)

[27b⁶]⁻$\frac{1}{3}$ = [3b²]⁻¹ = 1/ 3b²...............(2)

(1)/(2)

1/ 16a⁸ × 3b²

3b² / 16a⁸

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