Question

(64a^3+27b^3)÷(3b+4a)

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$\frac{64 {a}^{3} + 27 {b}^{3} }{3a + 4b} \\ \\ = \frac{(3a) {}^{3} + {(4b)}^{3} }{3a + 4b} \\ \\ use \: \: \: {x}^{3} + {y}^{3} = (x + y)( {x}^{2} + {y}^{2} + xy) \\ \\ = \frac{(3a + 4b)(9 {a}^{2} + 16 {b}^{2} + 12ab)}{3a + 4b} \\ \\ = 9 {a}^{2} + 16 {b}^{2} + 12ab$