Question

64a square-4b square- c square+4bc factorise

Answer 1

Solution : 64a² - 4b² - c² + 4bc

= 64a² - ( 4b² + c² - 4bc )

= 64a² - [ (2b)² + c² - 2 × 2b × c ]

Since a² + b² - 2ab = ( a - b )²

= 64a² - [( 2b - c )²]

= (8a)² - [( 2b - c )²]

Since a² - b² = ( a + b )( a - b )

= [ 8a + ( 2b - c )][ 8a - ( 2b - c )]

= ( 8a + 2b - c )( 8a - 2b + c )

Answer 2

Answer:

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