64a²-112ap+49p² factorize
plz answer it
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Answered by
2
Hey
Here is your answer,
64a²-112ap+49p²
Using the identity (a-b)^2 = a^2 - 2ab + b^2,
=(8a - 7b)^2
=(8a - 7b)(8a - 7b)
Hope it helps you!
Here is your answer,
64a²-112ap+49p²
Using the identity (a-b)^2 = a^2 - 2ab + b^2,
=(8a - 7b)^2
=(8a - 7b)(8a - 7b)
Hope it helps you!
Answered by
1
64a^2 is square of 8a, while 49p^2 is the square of 7p
so this resembles to the identity:-
(a-b)^2=a^2+b^2-2ab
similarly, 64a^2-2(8a)(7p)+49p^2 =(8a-7p)^2
hope this helps!
so this resembles to the identity:-
(a-b)^2=a^2+b^2-2ab
similarly, 64a^2-2(8a)(7p)+49p^2 =(8a-7p)^2
hope this helps!
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