Question

64a2+49b2+112ab .Please factorise

Answer 1

64a2+49b2+112ab

= (8a)2+(7b)2+2*8a*7b

= (8a+7b)2

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Answer 2

HERE IS YOUR ANSWER...⬇⬇

$\boxed{SOLUTION}$ ➡



$64a {}^{2} + 49 b {}^{2} + 112ab \\ \\ = 64a {}^{2} + 112ab + 49b {}^{2} \\ \\ = (8 a) {}^{2} + 2 \times 8 a\times 7 b + (7b) {}^{2} \\ \\ = (8 a+ 7b) {}^{2} \: \\ \\ = (8 a+ 7b)(8 a+7b )$

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