Question

64a²-9b²+42bc-49c². Factorise​

Answer 1

Answer:

64a

2

−9b

2

+42bc−49c

2

=64a

2

−[9b

2

−42bc+49c

2

]

=(8a)

2

−[(3b)

2

−2×3b×7c+(7c)

2

][∵a

2

+b

2

−2ab=(a−b)

2

anda

2

−b

2

=(a+b)(a−b)]

=(8a)

2

−(3b−7c)

2

=(8a+3b−7c)(8a−3b+7c)

Step-by-step explanation:

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