Question

64a3 – 27b3 – 114a2b + 108ab2​

Answer 1

Answer:

192a-81b-12ab

Step-by-step explanation:

if the a3 or b3 is not an exponent number then this is the answer.

64a3 – 27b3 – 114a2b + 108ab2​ (times the number together)

 ↓         ↓             ↓           ↓

192a-     81b-      228ab+  216ab (hope it helps, brainiest plz)

if it is an exponent number then this is the answer:64a3 – 27b3 – 114a2b + 108ab2​

Answer 2

Answer:

64a³– 27b³ – 114a²b + 108ab² = (4a-3b)³

Step-by-step explanation:

In the context to question;

we have factorize the given equation

64a³– 27b³ – 114a²b + 108ab²

(4a)³- (3b)³ - 3 (4a)² 3b +  3(4a)(3b)²

we know that

(a-b)³ = a³-b³-3a²b+3a²b

Therefore;

We can write it as ;

(4a)³- (3b)³ - 3 (4a)² 3b +  3(4a)(3b)² = (4a-3b)³

hence;

(4a-3b)³ is the answer.