Math, asked by siva211970yahoocom, 11 months ago

64a³-27b³-144a²b+108ab²​

Answers

Answered by harshit3754
12

Step-by-step explanation:

using identities =

(a+b)³= a³+b³+3ab(a+b)

so = 64a³-27b³-144a²b+105ab²

= (4a)³ + (-3b) ³ + 3*4a*-3b(4a-3b)

so (4a-3b) ³

Answer = (4a-3b) (4a-3b) (4a-3b

Answered by Anonymous
5

in this question we have to use an identity

(x-y)³=x³-y³-3xy(x-y)

64a³-27b³-144a²b+108ab²

=(4a)³-(3b)³-36ab(4a-3b)

=(4a-3b)³

=(4a-3b)(4a-3b)(4a-3b)

hope it helps u

please mark it as the brainliest.....

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