Question

64a³ - 27b³ - 144a²b + 108ab²Factorize by using appropriate identities.

Answer 1

64a3 - 27b3 - 144a2b + 108ab2
by using (a - b)3=a3 -b3 -3ab (a-b)
(4a)3 - (3b)3 - 3× 4a × 3b (4a-3b)
(4a - 3b)3
(4a - 3b) (4a - 3b) (4a - 3b)

Answer 2

Hi ,

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We know the algebraic identity :

x³ - y³ - 3x²y + 3xy² = ( x - y )³

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Here ,

It is given that ,

64a³ - 27b³ - 144a²b + 108ab²

= (4a)³-(3b)³-3×(4a )²×(3b)+3×(4a)(3b)²

= ( 4a - 3b )³

= ( 4a - 3b )( 4a - 3b )( 4a - 3b )

I hope this helps you.

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