Math, asked by Lpoiy, 1 year ago

64a³ - 27b³ - 147a²b + 108ab²


Factorise .....

Answers

Answered by Anonymous
7
Hello!

\sf 64a^{3}- 27b^{3} - 144a^{2}b + 108ab^{2} \\ \\ \implies \sf 64a^{3} - 27b^{3}- 144a^{2}b + 108ab^{2} \\ \\ \implies \sf (4a)^{3}- (3b)^{3} - 3(4a)^{2}(3b) + 3(4a)(3b)^{2} \\ \\ \implies \sf (4a - 3b)^{3} \\ \\ \implies \boxed{\red{\bf{(4a - 3b)(4a - 3b)(4a - 3b)}}}

saivivek16: text neatly
Answered by Anonymous
18

Heya. Mate

64a³ - 27b³ - 144a²b + 108ab²

= (4a)² + (-3b)³ -36ab (4a - 3b)

= (4a)³ - (-3b)³ + 3(4a)(-3b)[4a + (-3b)]

= {4a + (-3b)}³ = (4a - 3b)³

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