Question

64g of oxygen at s.t.p contains

Answer 1

Answer:

From a container having 64g oxygen ,11.2 l oxygen gas at s.t.p and 6.022 *10^23 oxygen atoms are -

Answer 2

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↪️Atomic weight of oxygen = 16

Atomic weight of oxygen = 16At STP,

Atomic weight of oxygen = 16At STP, 1 mole of O2 = 16 x 2

Atomic weight of oxygen = 16At STP, 1 mole of O2 = 16 x 2 = 32 g

Atomic weight of oxygen = 16At STP, 1 mole of O2 = 16 x 2 = 32 gWe know,

Atomic weight of oxygen = 16At STP, 1 mole of O2 = 16 x 2 = 32 gWe know,1 mole = 22.4 litres

Atomic weight of oxygen = 16At STP, 1 mole of O2 = 16 x 2 = 32 gWe know,1 mole = 22.4 litres1 mole of O2 = 22.4 litres

Atomic weight of oxygen = 16At STP, 1 mole of O2 = 16 x 2 = 32 gWe know,1 mole = 22.4 litres1 mole of O2 = 22.4 litres32 g of O2 = 22.4 litres

Atomic weight of oxygen = 16At STP, 1 mole of O2 = 16 x 2 = 32 gWe know,1 mole = 22.4 litres1 mole of O2 = 22.4 litres32 g of O2 = 22.4 litres64 g of O2 = 64 x 22.4 / 32

Atomic weight of oxygen = 16At STP, 1 mole of O2 = 16 x 2 = 32 gWe know,1 mole = 22.4 litres1 mole of O2 = 22.4 litres32 g of O2 = 22.4 litres64 g of O2 = 64 x 22.4 / 32 = 44.8 litres

Atomic weight of oxygen = 16At STP, 1 mole of O2 = 16 x 2 = 32 gWe know,1 mole = 22.4 litres1 mole of O2 = 22.4 litres32 g of O2 = 22.4 litres64 g of O2 = 64 x 22.4 / 32 = 44.8 litresTherefore, from the above calculations, we can infer that 64 g of oxygen is 44.8 litres at STP