Question

64go2 at S.T.P occupies Volume
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Answer 1

Explanation:

At STP, one mole of any gas occupies 22.4 litres of volume. One mole of a gas is given by the Avogadro's number i.e. NA and it is given as 6.023×1023. According to this, one mole of hydrogen gas at STP will occupy 22.4 L of volume.

According to reaction, At STP; 1 mole of acetylene that is 22.4L require 5/2 moles of oxygen that is 52×22.4 = 56L for complete combustion.

So, if 1 mole occupies 22.4 L, the imediate conclusion is that a bigger number of moles will occupy more than 22.4 L, and a smaller number of moles will occupy less than 22.4 L. In your case, 3 moles of gas will occupy 3 times more volume than 1 mole of gas.

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