Question

64m-45n=289;45m-64n=365
solve the simultaneous equation step by step​

Answer 1

Answer:

I hope it is correct answer

Answer 2

Answer:

64m-45n=289(eqn 1)

45m-64n=365(eqn2)

Adding eqn 1 & 2

109m-109n=654

Dividing whole by 109,

We get,

m-n=6(eqn3)

Subtracting eqn 1 & 2

19m+19n=76

Dividing whole by 19,

We get,

m+n=4(eqn4)

Subtracting eqn 3 & 4

We get,

2m=2

Therefore:m=2÷2

m=1

Substituting "m=1" in eqn 1

64m-45n=289

64×1-45n=289

64-45n=289

45n=289-64

45n=225

n=225÷45

n=5