Question

64m³-343n³
factorise this ⬆⬆
class 9th
Thanks:)​

Answer 1

Answer:

(4m)³-(7n)³

using a³-b³=(a-b) (a²+ab+b²)

(4m-7n) {(4m)²+4m.7n+(7n)³}

Answer 2

Answer:

$(4m - 7n)(16 {m}^{2} + 28mn + 49 {n}^{2} )$

Explanation:

$64 {m}^{3} - 343 {n}^{3} \\ = {(4m)}^{3} - {(7n)}^{3}$

According to the formula,

${x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ = (4m - 7n)( {(4m)}^{2} + 4m \times 7n + {(7n)}^{2} ) \\ = (4m - 7n)(16 {m}^{2} + 28mn + 49 {n}^{2} )$

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