64x^3-27y^3+8z^3+72xyz
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Given: The term 64x^3 - 27y^3 + 8z^3 + 72xyz
To find: Factorise it.
Solution:
- Now we have given the term as 64x^3 - 27y^3 + 8z^3 + 72xyz
- We can rewrite it as:
(4x)^3 + (-3y)^3 + (2z)^3 - 3(4x)(-3y)(2z)
- Now we know the formula:
a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca)
- So applying it, we get:
(4x - 3y + 2z) ((4x)^2 + (-3y)^2 + (2z)^2 - (4x)(-3y) + (3y)(2z) - 2z)(4x))
(4x - 3y + 2z) (16x^2 + 9y^2 + 4z^2 + 12xy + 6yz - 8zx)
Answer:
So the factors are:
(4x - 3y + 2z) (16x^2 + 9y^2 + 4z^2 + 12xy + 6yz - 8zx)
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