Question

64x^6-729y^6
Factorise​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$64x^6-729y^6=(8x^3+27y^3)(2x-3y)(4x^2+6xy+9y^2)$

Step-by-step explanation:

Given : Expression $64x^6-729y^6$

To find : Factories the expression ?

Solution :

The expression is written as,

$64x^6-729y^6=(8x^3)^2-(27y^3)^2$

Applying $a^2-b^2=(a+b)(a-b)$

$64x^6-729y^6=(8x^3+27y^3)(8x^3-27y^3)$

$64x^6-729y^6=(8x^3+27y^3)((2x)^3-(3y)^3)$

Applying identity, $a^3-b^3=(a-b)(a^2+ab+b^2)$

$64x^6-729y^6=(8x^3+27y^3)(2x-3y)((2x)^2+(2x)(3y)+(3y)^2)$

$64x^6-729y^6=(8x^3+27y^3)(2x-3y)(4x^2+6xy+9y^2)$

Therefore, the factories form is $64x^6-729y^6=(8x^3+27y^3)(2x-3y)(4x^2+6xy+9y^2)$