64x³ +1
FACTORISE IT
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ANSWER:
- Factorisation of the above expression is (4x+1)(16x²+1-4x)
GIVEN:
- P(x) = 64x³+1
TO FIND:
- P(x) = 64x³+1
Formula used:
- a³+b³ = (a+b)(a²+b²-ab)
SOLUTION:
= 64x³+1
= (4x)³ + (1)³
= (4x+1)[(4x)²+(1)²-4x(1)]
= (4x+1)(16x²+1-4x)
Factorisation of the above expression is (4x+1)(16x²+1-4x)
NOTE:
Some important formulas:
(a+b)² = a²+b²+2ab
(a-b)² = a²+b²-2ab
(a+b)(a-b) = a²-b²
(a+b)³ = a³+b³+3ab(a+b)
(a-b)³ = a³-b³-3ab(a-b)
a³+b³ = (a+b)(a²+b²-ab)
a³-b³ = (a-b)(a²+b²+ab)
(a+b)² = (a-b)²+4ab
(a-b)² = (a+b)²-4ab
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