Math, asked by vasupareek2004, 8 months ago

64x3÷125-96x2÷25-8+48x÷5​

Answers

Answered by Anonymous
0

Answer:

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2". 1 more similar replacement(s).

STEP

1

:

x

Simplify —

5

Equation at the end of step

1

:

(x3) (x2) x

(((64•————)-8)-(96•————))+(48•—)

125 25 5

STEP

2

:

x2

Simplify ——

25

Equation at the end of step

2

:

(x3) x2 48x

(((64•————)-8)-(96•——))+———

125 25 5

STEP

3

:

x3

Simplify ———

125

Equation at the end of step

3

:

x3 96x2 48x

(((64 • ———) - 8) - ————) + ———

125 25 5

STEP

4

:

Rewriting the whole as an Equivalent Fraction

4.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 125 as the denominator :

8 8 • 125

8 = — = ———————

1 125

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

4.2 Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

64x3 - (8 • 125) 64x3 - 1000

———————————————— = ———————————

125 125

Equation at the end of step

4

:

(64x3 - 1000) 96x2 48x

(————————————— - ————) + ———

125 25 5

STEP

5

:

STEP

6

:

Pulling out like terms

6.1 Pull out like factors :

64x3 - 1000 = 8 • (8x3 - 125)

Trying to factor as a Difference of Cubes:

6.2 Factoring: 8x3 - 125

Theory : A difference of two perfect cubes, a3 - b3 can be factored into

(a-b) • (a2 +ab +b2)

Proof : (a-b)•(a2+ab+b2) =

a3+a2b+ab2-ba2-b2a-b3 =

a3+(a2b-ba2)+(ab2-b2a)-b3 =

a3+0+0+b3 =

a3+b3

Check : 8 is the cube of 2

Check : 125 is the cube of 5

Check : x3 is the cube of x1

Factorization is :

(2x - 5) • (4x2 + 10x + 25)

Trying to factor by splitting the middle term

6.3 Factoring 4x2 + 10x + 25

The first term is, 4x2 its coefficient is 4 .

The middle term is, +10x its coefficient is 10 .

The last term, "the constant", is +25

Step-1 : Multiply the coefficient of the first term by the constant 4 • 25 = 100

Step-2 : Find two factors of 100 whose sum equals the coefficient of the middle term, which is 10 .

-100 + -1 = -101

-50 + -2 = -52

-25 + -4 = -29

-20 + -5 = -25

-10 + -10 = -20

-5 + -20 = -25

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